In my recent post about double emulation in GLSL I tested the shader code on my ATI GPU. That was a mistake… Mauna pointed out that the double emulation shader does not work on NVIDIA GPUs. I checked that and it proved that this was not a single problem on a specific card.

I reckon that it must be some weird optimization on NVIDIA cards that break the emulation code. So I searched for a way to disable these optimizations. After some googling I found an old blog entry by Cyril Crassin (check out his new blog if you are into 3D graphics) which helped me out with this problem.


To turn off the NVIDIA optimizations I had to add the following lines to the shader code.

    #pragma optionNV(fastmath off)
    #pragma optionNV(fastprecision off)

Now it should work fine with NVIDIA GPUs. Let me know if there are still some issues.

Download updated version:

I have also found a handy tool called NVEmulate to examine the GLSL compiler output and other stuff to analyze GLSL assembly on NVIDIA GPUs.


Jethro provided the division function:

    vec2 ds_div(vec2 dsa, vec2 dsb)
    vec2 dsc;
    float c11, c21, c2, e, s1, s2, t1, t2, t11, t12, t21, t22;
    float a1, a2, b1, b2, cona, conb, split = 8193.;

    s1 = dsa.x / dsb.x;

    cona = s1 * split;
    conb = dsb.x * split;
    a1 = cona  (cona  s1);
    b1 = conb  (conb  dsb.x);
    a2 = s1  a1;
    b2 = dsb.x  b1;

    c11 = s1 * dsb.x;
    c21 = (((a1 * b1  c11) + a1 * b2) + a2 * b1) + a2 * b2;
    c2 = s1 * dsb.y;

    t1 = c11 + c2;
    e = t1  c11;
    t2 = ((c2  e) + (c11  (t1  e))) + c21;

    t12 = t1 + t2;
    t22 = t2  (t12  t1);

    t11 = dsa[0]  t12;
    e = t11  dsa[0];
    t21 = ((-t12  e) + (dsa.x  (t11  e))) + dsa.y  t22;

    s2 = (t11 + t21) / dsb.x;

    dsc.x = s1 + s2;
    dsc.y = s2  (dsc.x  s1);

    return dsc;